Q) The perimeter of Rhombus is 146 cm & one of its diagonals 55 cm. Find other diagonal and area of rhombus ?
Solution
Let ABCD be the rhombus.
Therefore, AB = 146/4 = 36.5 cm
AO = 55/2 = 27.5 cm
We can see that the diagonals are making 90 degree angle.
using Pythagoras theorem BO = √ 36.5^2 - 27.5^2 = 24 cm
hence other diagonal is 48 cm.
so, area = 1/2 * 48 * 55 = 1320 sq. cm.
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